Make bitfield assignment operator public

This change needs to be made to get the code compiling again. It was suggested after a conversation with Lioncash.

The conversation can be seen here: https://user-images.githubusercontent.com/20753089/45064197-b6107800-b0b2-11e8-9db8-f696299fb86a.PNG

1 files changed, 2 insertions, 6 deletions

diff --git a/src/common/bit_field.h b/src/common/bit_field.h
index bd9e21e1e..639efe22d 100644
--- a/src/common/bit_field.h
+++ b/src/common/bit_field.h
@@ -112,12 +112,6 @@
 template <std::size_t Position, std::size_t Bits, typename T, typename EndianTag = LETag>
 struct BitField {
 private:
-    // We hide the copy assigment operator here, because the default copy
-    // assignment would copy the full storage value, rather than just the bits
-    // relevant to this particular bit field.
-    // We don't delete it because we want BitField to be trivially copyable.
-    constexpr BitField& operator=(const BitField&) = default;
-
     // UnderlyingType is T for non-enum types and the underlying type of T if
     // T is an enumeration. Note that T is wrapped within an enable_if in the
     // former case to workaround compile errors which arise when using
@@ -131,6 +125,8 @@ private:
     using StorageTypeWithEndian = typename AddEndian<StorageType, EndianTag>::type;
 
 public:
+    BitField& operator=(const BitField&) = default;
+
     /// Constants to allow limited introspection of fields if needed
     static constexpr std::size_t position = Position;
     static constexpr std::size_t bits = Bits;